What are the solutions to the equation 36y^2-54y-16=0 ?

The solutions to the equation 36y^2-54y-16=0 are y=(9+sqrt(145))/(12),y=(9-sqrt(145))/(12)

Find the zeros of 36y^2-54y-16=0

The zeros of 36y^2-54y-16=0 are y=(9+sqrt(145))/(12),y=(9-sqrt(145))/(12)

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36 y^{2} - 54 y - 16 = 0

y = \frac{9 + 145}{12}, y = \frac{9 - 145}{12}

Decimal Notation

y = 1.75346 \dots, y = - 0.25346 \dots

Solution steps

36 y^{2} - 54 y - 16 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 54 ) \pm ( - 54 ) ^{2} - 4 \cdot 36 ( - 16 )}{2 \cdot 36}

(- 54)^{2} - 4 \cdot 36 (- 16) = 6145

y_{1, 2} = \frac{- ( - 54 ) \pm 6 145}{2 \cdot 36}

Separate the solutions

y_{1} = \frac{- ( - 54 ) + 6 145}{2 \cdot 36}, y_{2} = \frac{- ( - 54 ) - 6 145}{2 \cdot 36}

y = \frac{- ( - 54 ) + 6 145}{2 \cdot 36} : \frac{9 + 145}{12}

y = \frac{- ( - 54 ) - 6 145}{2 \cdot 36} : \frac{9 - 145}{12}

The solutions to the quadratic equation are:

y = \frac{9 + 145}{12}, y = \frac{9 - 145}{12}

4 p^{2} - 5 p - 51 = 0

2 x^{(2)} + 3 = 6 x

x, f = u (x^{2})

- x^{2} - 2 x + 8

x^{2} + 62525 x + 62500000 = 0

What are the solutions to the equation 36y^2-54y-16=0 ?
The solutions to the equation 36y^2-54y-16=0 are y=(9+sqrt(145))/(12),y=(9-sqrt(145))/(12)
Find the zeros of 36y^2-54y-16=0
The zeros of 36y^2-54y-16=0 are y=(9+sqrt(145))/(12),y=(9-sqrt(145))/(12)