What are the solutions to the equation 800= n/2 (30+(n-1)10) ?

The solutions to the equation 800= n/2 (30+(n-1)10) are n=-1+sqrt(161),n=-1-sqrt(161)

Find the zeros of 800= n/2 (30+(n-1)10)

The zeros of 800= n/2 (30+(n-1)10) are n=-1+sqrt(161),n=-1-sqrt(161)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

800 = \frac{n}{2} (30 + (n - 1) 10)

n = - 1 + 161, n = - 1 - 161

Decimal Notation

n = 11.68857 \dots, n = - 13.68857 \dots

Solution steps

800 = \frac{n}{2} (30 + (n - 1) \cdot 10)

Multiply both sides by

2

1600 = n (30 + 10 (n - 1))

Expand

n (30 + 10 (n - 1)) : 10 n^{2} + 20 n

1600 = 10 n^{2} + 20 n

Switch sides

10 n^{2} + 20 n = 1600

Move

1600

to the left side

10 n^{2} + 20 n - 1600 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 10 ( - 1600 )}{2 \cdot 10}

2 0^{2} - 4 \cdot 10 (- 1600) = 20161

n_{1, 2} = \frac{- 20 \pm 20 161}{2 \cdot 10}

Separate the solutions

n_{1} = \frac{- 20 + 20 161}{2 \cdot 10}, n_{2} = \frac{- 20 - 20 161}{2 \cdot 10}

n = \frac{- 20 + 20 161}{2 \cdot 10} : - 1 + 161

n = \frac{- 20 - 20 161}{2 \cdot 10} : - 1 - 161

The solutions to the quadratic equation are:

n = - 1 + 161, n = - 1 - 161

(8 + x) \cdot 3 x - (8 + x) \cdot 7 = 0

c^{2} - 32 = 0

3 x^{2} + x - 1 = (2 x + 9) (x - 1)

x, 3 x^{2} - 5 x = 3 x + 5

5 x^{2} = 6

What are the solutions to the equation 800= n/2 (30+(n-1)10) ?
The solutions to the equation 800= n/2 (30+(n-1)10) are n=-1+sqrt(161),n=-1-sqrt(161)
Find the zeros of 800= n/2 (30+(n-1)10)
The zeros of 800= n/2 (30+(n-1)10) are n=-1+sqrt(161),n=-1-sqrt(161)