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What are the solutions to the equation (2x+3)^2=18 ?
The solutions to the equation (2x+3)^2=18 are x=(3sqrt(2)-3)/2 ,x=(-3sqrt(2)-3)/2Find the zeros of (2x+3)^2=18
The zeros of (2x+3)^2=18 are x=(3sqrt(2)-3)/2 ,x=(-3sqrt(2)-3)/2