What are the solutions to the equation m^2-4m=5 ?

The solutions to the equation m^2-4m=5 are m=5,m=-1

Find the zeros of m^2-4m=5

The zeros of m^2-4m=5 are m=5,m=-1

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m^{2} - 4 m = 5

m = 5, m = - 1

Solution steps

m^{2} - 4 m = 5

Move

5

to the left side

m^{2} - 4 m - 5 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 5) = 6

m_{1, 2} = \frac{- ( - 4 ) \pm 6}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 4 ) + 6}{2 \cdot 1}, m_{2} = \frac{- ( - 4 ) - 6}{2 \cdot 1}

m = \frac{- ( - 4 ) + 6}{2 \cdot 1} : 5

m = \frac{- ( - 4 ) - 6}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

m = 5, m = - 1

- 2 x^{2} - 7 x - 1 = 0

3 x^{2} + 2 x - 6

s^{2} = 25

(x + 5)^{3} - x^{3} - 1 5^{2} = 50

y^{2} - y - 3 = 0

What are the solutions to the equation m^2-4m=5 ?
The solutions to the equation m^2-4m=5 are m=5,m=-1
Find the zeros of m^2-4m=5
The zeros of m^2-4m=5 are m=5,m=-1