What are the solutions to the equation 0=-x^2+14x ?

The solutions to the equation 0=-x^2+14x are x=0,x=14

Find the zeros of 0=-x^2+14x

The zeros of 0=-x^2+14x are x=0,x=14

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0 = - x^{2} + 14 x

x = 0, x = 14

Solution steps

0 = - x^{2} + 14 x

Switch sides

- x^{2} + 14 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

1 4^{2} - 4 (- 1) \cdot 0 = 14

x_{1, 2} = \frac{- 14 \pm 14}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 14 + 14}{2 ( - 1 )}, x_{2} = \frac{- 14 - 14}{2 ( - 1 )}

x = \frac{- 14 + 14}{2 ( - 1 )} : 0

x = \frac{- 14 - 14}{2 ( - 1 )} : 14

The solutions to the quadratic equation are:

x = 0, x = 14

x^{2} - 12 x + 43

- 5 x^{2} + 94.8 x

7 b - 3 b^{2} = 5 b^{2}

8 x^{2} - 3 x - 2 = 0

x^{2} - 2 x - 62 = 0

What are the solutions to the equation 0=-x^2+14x ?
The solutions to the equation 0=-x^2+14x are x=0,x=14
Find the zeros of 0=-x^2+14x
The zeros of 0=-x^2+14x are x=0,x=14