What are the solutions to the equation n^2=-9-6n ?

The solutions to the equation n^2=-9-6n are n=-3

Find the zeros of n^2=-9-6n

The zeros of n^2=-9-6n are n=-3

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n^{2} = - 9 - 6 n

n = - 3

Solution steps

n^{2} = - 9 - 6 n

Move

6 n

to the left side

n^{2} + 6 n = - 9

Move

9

to the left side

n^{2} + 6 n + 9 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 9 = 0

n_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 1}

n = \frac{- 6}{2 \cdot 1}

\frac{- 6}{2 \cdot 1} = - 3

n = - 3

The solution to the quadratic equation is:

n = - 3

t^{2} + 16 t - 4 = 0

\frac{n ( n + 1 )}{2} = 575

x^{2} - 8 x + c

3 x^{2} - 9 x + 4 = 0

\frac{3 ( x ^{2} + 6 )}{2} = 1

What are the solutions to the equation n^2=-9-6n ?
The solutions to the equation n^2=-9-6n are n=-3
Find the zeros of n^2=-9-6n
The zeros of n^2=-9-6n are n=-3