What are the solutions to the equation (3(x^2+6))/2 =1 ?

The solutions to the equation (3(x^2+6))/2 =1 are x= 4/(sqrt(3))i,x=-4/(sqrt(3))i

Find the zeros of (3(x^2+6))/2 =1

The zeros of (3(x^2+6))/2 =1 are x= 4/(sqrt(3))i,x=-4/(sqrt(3))i

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\frac{3 ( x ^{2} + 6 )}{2} = 1

x = \frac{4}{3} i, x = - \frac{4}{3} i

Solution steps

\frac{3 ( x ^{2} + 6 )}{2} = 1

Multiply both sides by

2

3 (x^{2} + 6) = 2

Divide both sides by

3

x^{2} + 6 = \frac{2}{3}

Move

6

to the right side

x^{2} = - \frac{16}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{16}{3}, x = - - \frac{16}{3}

- \frac{16}{3} = \frac{4}{3} i

- - \frac{16}{3} = - \frac{4}{3} i

x = \frac{4}{3} i, x = - \frac{4}{3} i

4 x^{2} + 16 x + 1 = 0

(1 - 3) x^{2} + 3 x - 4 = 0

3 x^{2} - 20 x - 30 = 0

8 x^{2} - 6 x + 0 = 0

(x - 1)^{2} - 2 x = 0

What are the solutions to the equation (3(x^2+6))/2 =1 ?
The solutions to the equation (3(x^2+6))/2 =1 are x= 4/(sqrt(3))i,x=-4/(sqrt(3))i
Find the zeros of (3(x^2+6))/2 =1
The zeros of (3(x^2+6))/2 =1 are x= 4/(sqrt(3))i,x=-4/(sqrt(3))i