What are the solutions to the equation (x-1)^2-2x=0 ?

The solutions to the equation (x-1)^2-2x=0 are x=2+sqrt(3),x=2-sqrt(3)

Find the zeros of (x-1)^2-2x=0

The zeros of (x-1)^2-2x=0 are x=2+sqrt(3),x=2-sqrt(3)

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(x - 1)^{2} - 2 x = 0

x = 2 + 3, x = 2 - 3

Decimal Notation

x = 3.73205 \dots, x = 0.26794 \dots

Solution steps

(x - 1)^{2} - 2 x = 0

Expand

(x - 1)^{2} - 2 x : x^{2} - 4 x + 1

x^{2} - 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot 1 = 23

x_{1, 2} = \frac{- ( - 4 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 3}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 3}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 3}{2 \cdot 1} : 2 + 3

x = \frac{- ( - 4 ) - 2 3}{2 \cdot 1} : 2 - 3

The solutions to the quadratic equation are:

x = 2 + 3, x = 2 - 3

n^{2} - 51 n + 270 = 0

3 (x^{2} - 18) = 21

x^{2} + 2^{2} = 1 0^{2}

2 x^{2} - 14 x + 26 = 0

10 x^{2} + 12 x = - 2

What are the solutions to the equation (x-1)^2-2x=0 ?
The solutions to the equation (x-1)^2-2x=0 are x=2+sqrt(3),x=2-sqrt(3)
Find the zeros of (x-1)^2-2x=0
The zeros of (x-1)^2-2x=0 are x=2+sqrt(3),x=2-sqrt(3)