What are the solutions to the equation 10x^2+12x=-2 ?

The solutions to the equation 10x^2+12x=-2 are x=-1/5 ,x=-1

Find the zeros of 10x^2+12x=-2

The zeros of 10x^2+12x=-2 are x=-1/5 ,x=-1

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10 x^{2} + 12 x = - 2

x = - \frac{1}{5}, x = - 1

Decimal

x = - 0.2, x = - 1

Solution steps

10 x^{2} + 12 x = - 2

Move

2

to the left side

10 x^{2} + 12 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 10 \cdot 2}{2 \cdot 10}

1 2^{2} - 4 \cdot 10 \cdot 2 = 8

x_{1, 2} = \frac{- 12 \pm 8}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 12 + 8}{2 \cdot 10}, x_{2} = \frac{- 12 - 8}{2 \cdot 10}

x = \frac{- 12 + 8}{2 \cdot 10} : - \frac{1}{5}

x = \frac{- 12 - 8}{2 \cdot 10} : - 1

The solutions to the quadratic equation are:

x = - \frac{1}{5}, x = - 1

6 x^{2} + 12 x + 390 = 0

x, u = x^{2} + y

x^{2} + 10 x - 40 = 0

30 y^{2} - 25000 y + 4375000 = 0

x^{2} - 2 x - 24 = 0

What are the solutions to the equation 10x^2+12x=-2 ?
The solutions to the equation 10x^2+12x=-2 are x=-1/5 ,x=-1
Find the zeros of 10x^2+12x=-2
The zeros of 10x^2+12x=-2 are x=-1/5 ,x=-1