What are the solutions to the equation 5x^2+7x-j=0 ?

The solutions to the equation 5x^2+7x-j=0 are x=(-7+sqrt(49+20j))/(10),x=(-7-sqrt(49+20j))/(10)

Find the zeros of 5x^2+7x-j=0

The zeros of 5x^2+7x-j=0 are x=(-7+sqrt(49+20j))/(10),x=(-7-sqrt(49+20j))/(10)

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5 x^{2} + 7 x - j = 0

x = \frac{- 7 + 49 + 20 j}{10}, x = \frac{- 7 - 49 + 20 j}{10}

Solution steps

5 x^{2} + 7 x - j = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 5 ( - j )}{2 \cdot 5}

Simplify

7^{2} - 4 \cdot 5 (- j) : 49 + 20 j

x_{1, 2} = \frac{- 7 \pm 49 + 20 j}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 7 + 49 + 20 j}{2 \cdot 5}, x_{2} = \frac{- 7 - 49 + 20 j}{2 \cdot 5}

x = \frac{- 7 + 49 + 20 j}{2 \cdot 5} : \frac{- 7 + 49 + 20 j}{10}

x = \frac{- 7 - 49 + 20 j}{2 \cdot 5} : \frac{- 7 - 49 + 20 j}{10}

The solutions to the quadratic equation are:

x = \frac{- 7 + 49 + 20 j}{10}, x = \frac{- 7 - 49 + 20 j}{10}

k (k - 5) = 0

(x - 1)^{2} - (2 x + 1) = 3 (x^{2} - 2)

x, 2 x^{2} + 32 y^{2} = - 4 x y

0 = - 16 x^{2} + 40 x + 62

85 q = - q^{2} + 5000

What are the solutions to the equation 5x^2+7x-j=0 ?
The solutions to the equation 5x^2+7x-j=0 are x=(-7+sqrt(49+20j))/(10),x=(-7-sqrt(49+20j))/(10)
Find the zeros of 5x^2+7x-j=0
The zeros of 5x^2+7x-j=0 are x=(-7+sqrt(49+20j))/(10),x=(-7-sqrt(49+20j))/(10)