What are the solutions to the equation 85q=-q^2+5000 ?

The solutions to the equation 85q=-q^2+5000 are q=-125,q=40

Find the zeros of 85q=-q^2+5000

The zeros of 85q=-q^2+5000 are q=-125,q=40

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85 q = - q^{2} + 5000

q = - 125, q = 40

Solution steps

85 q = - q^{2} + 5000

Switch sides

- q^{2} + 5000 = 85 q

Move

85 q

to the left side

- q^{2} + 5000 - 85 q = 0

Write in the standard form

a x^{2} + b x + c = 0

- q^{2} - 85 q + 5000 = 0

Solve with the quadratic formula

q_{1, 2} = \frac{- ( - 85 ) \pm ( - 85 ) ^{2} - 4 ( - 1 ) \cdot 5000}{2 ( - 1 )}

(- 85)^{2} - 4 (- 1) \cdot 5000 = 165

q_{1, 2} = \frac{- ( - 85 ) \pm 165}{2 ( - 1 )}

Separate the solutions

q_{1} = \frac{- ( - 85 ) + 165}{2 ( - 1 )}, q_{2} = \frac{- ( - 85 ) - 165}{2 ( - 1 )}

q = \frac{- ( - 85 ) + 165}{2 ( - 1 )} : - 125

q = \frac{- ( - 85 ) - 165}{2 ( - 1 )} : 40

The solutions to the quadratic equation are:

q = - 125, q = 40

2 m^{2} - m - 1 = 0

15 x^{2} + 10.5 x - 2.7 = 0

2 x^{2} + 7

7 x^{2} + 7 = 14 x

x, 2 x^{2} - 5 x + 4 = 0

What are the solutions to the equation 85q=-q^2+5000 ?
The solutions to the equation 85q=-q^2+5000 are q=-125,q=40
Find the zeros of 85q=-q^2+5000
The zeros of 85q=-q^2+5000 are q=-125,q=40