What are the solutions to the equation 2m^2-m-1=0 ?

The solutions to the equation 2m^2-m-1=0 are m=1,m=-1/2

Find the zeros of 2m^2-m-1=0

The zeros of 2m^2-m-1=0 are m=1,m=-1/2

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2 m^{2} - m - 1 = 0

m = 1, m = - \frac{1}{2}

Decimal Notation

m = 1, m = - 0.5

Solution steps

2 m^{2} - m - 1 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 1) = 3

m_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 \cdot 2}

Separate the solutions

m_{1} = \frac{- ( - 1 ) + 3}{2 \cdot 2}, m_{2} = \frac{- ( - 1 ) - 3}{2 \cdot 2}

m = \frac{- ( - 1 ) + 3}{2 \cdot 2} : 1

m = \frac{- ( - 1 ) - 3}{2 \cdot 2} : - \frac{1}{2}

The solutions to the quadratic equation are:

m = 1, m = - \frac{1}{2}

15 x^{2} + 10.5 x - 2.7 = 0

2 x^{2} + 7

7 x^{2} + 7 = 14 x

x, 2 x^{2} - 5 x + 4 = 0

- 30 v - 25 = 9 v^{2}

What are the solutions to the equation 2m^2-m-1=0 ?
The solutions to the equation 2m^2-m-1=0 are m=1,m=-1/2
Find the zeros of 2m^2-m-1=0
The zeros of 2m^2-m-1=0 are m=1,m=-1/2