What are the solutions to the equation 7x^2+7=14x ?

The solutions to the equation 7x^2+7=14x are x=1

Find the zeros of 7x^2+7=14x

The zeros of 7x^2+7=14x are x=1

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7 x^{2} + 7 = 14 x

x = 1

Solution steps

7 x^{2} + 7 = 14 x

Move

14 x

to the left side

7 x^{2} + 7 - 14 x = 0

Write in the standard form

a x^{2} + b x + c = 0

7 x^{2} - 14 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 7 \cdot 7}{2 \cdot 7}

(- 14)^{2} - 4 \cdot 7 \cdot 7 = 0

x_{1, 2} = \frac{- ( - 14 ) \pm 0}{2 \cdot 7}

x = \frac{- ( - 14 )}{2 \cdot 7}

\frac{- ( - 14 )}{2 \cdot 7} = 1

x = 1

The solution to the quadratic equation is:

x = 1

x, 2 x^{2} - 5 x + 4 = 0

- 30 v - 25 = 9 v^{2}

x, CT (x) = x^{2} - 50 x - 10

3 (x - 6)^{2} = 80

8 n^{2} + 27 n - 20 = 0

What are the solutions to the equation 7x^2+7=14x ?
The solutions to the equation 7x^2+7=14x are x=1
Find the zeros of 7x^2+7=14x
The zeros of 7x^2+7=14x are x=1