What are the solutions to the equation 8n^2+27n-20=0 ?

The solutions to the equation 8n^2+27n-20=0 are n= 5/8 ,n=-4

Find the zeros of 8n^2+27n-20=0

The zeros of 8n^2+27n-20=0 are n= 5/8 ,n=-4

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8 n^{2} + 27 n - 20 = 0

n = \frac{5}{8}, n = - 4

Decimal Notation

n = 0.625, n = - 4

Solution steps

8 n^{2} + 27 n - 20 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 27 \pm 2 7 ^{2} - 4 \cdot 8 ( - 20 )}{2 \cdot 8}

2 7^{2} - 4 \cdot 8 (- 20) = 37

n_{1, 2} = \frac{- 27 \pm 37}{2 \cdot 8}

Separate the solutions

n_{1} = \frac{- 27 + 37}{2 \cdot 8}, n_{2} = \frac{- 27 - 37}{2 \cdot 8}

n = \frac{- 27 + 37}{2 \cdot 8} : \frac{5}{8}

n = \frac{- 27 - 37}{2 \cdot 8} : - 4

The solutions to the quadratic equation are:

n = \frac{5}{8}, n = - 4

7 x + 2 = - 3 x^{2}

3 x^{2} - x - 9 = 0

- 8 x^{2} - 62 x + 16 = 0

(4 + 3 y)^{2} + y^{2} = 146

x, x^{2} y - x = 4 y

What are the solutions to the equation 8n^2+27n-20=0 ?
The solutions to the equation 8n^2+27n-20=0 are n= 5/8 ,n=-4
Find the zeros of 8n^2+27n-20=0
The zeros of 8n^2+27n-20=0 are n= 5/8 ,n=-4