What are the solutions to the equation 3x^2-x-9=0 ?

The solutions to the equation 3x^2-x-9=0 are x=(1+sqrt(109))/6 ,x=(1-sqrt(109))/6

Find the zeros of 3x^2-x-9=0

The zeros of 3x^2-x-9=0 are x=(1+sqrt(109))/6 ,x=(1-sqrt(109))/6

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3 x^{2} - x - 9 = 0

x = \frac{1 + 109}{6}, x = \frac{1 - 109}{6}

Decimal Notation

x = 1.90671 \dots, x = - 1.57338 \dots

Solution steps

3 x^{2} - x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 (- 9) = 109

x_{1, 2} = \frac{- ( - 1 ) \pm 109}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 109}{2 \cdot 3}, x_{2} = \frac{- ( - 1 ) - 109}{2 \cdot 3}

x = \frac{- ( - 1 ) + 109}{2 \cdot 3} : \frac{1 + 109}{6}

x = \frac{- ( - 1 ) - 109}{2 \cdot 3} : \frac{1 - 109}{6}

The solutions to the quadratic equation are:

x = \frac{1 + 109}{6}, x = \frac{1 - 109}{6}

- 8 x^{2} - 62 x + 16 = 0

(4 + 3 y)^{2} + y^{2} = 146

x, x^{2} y - x = 4 y

- x^{2} + 4 x = 0

4 x^{2} + 12 x + 3 = 0

What are the solutions to the equation 3x^2-x-9=0 ?
The solutions to the equation 3x^2-x-9=0 are x=(1+sqrt(109))/6 ,x=(1-sqrt(109))/6
Find the zeros of 3x^2-x-9=0
The zeros of 3x^2-x-9=0 are x=(1+sqrt(109))/6 ,x=(1-sqrt(109))/6