What are the solutions to the equation 0=x(x-2)-3 ?

The solutions to the equation 0=x(x-2)-3 are x=3,x=-1

Find the zeros of 0=x(x-2)-3

The zeros of 0=x(x-2)-3 are x=3,x=-1

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0 = x (x - 2) - 3

x = 3, x = - 1

Solution steps

0 = x (x - 2) - 3

Expand

x (x - 2) - 3 : x^{2} - 2 x - 3

0 = x^{2} - 2 x - 3

Switch sides

x^{2} - 2 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 3) = 4

x_{1, 2} = \frac{- ( - 2 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 4}{2 \cdot 1}

x = \frac{- ( - 2 ) + 4}{2 \cdot 1} : 3

x = \frac{- ( - 2 ) - 4}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 3, x = - 1

50 = 50 + 2 t - 0.0625 t^{2}

(2 x - 1)^{2} - 1 = 19

x, x^{2} - y^{2} = x y

a^{2} + a^{2} = x^{2}

4 x^{2} - 5 x^{2} = - 12

What are the solutions to the equation 0=x(x-2)-3 ?
The solutions to the equation 0=x(x-2)-3 are x=3,x=-1
Find the zeros of 0=x(x-2)-3
The zeros of 0=x(x-2)-3 are x=3,x=-1