What are the solutions to the equation 4x^2-11x+3=6x-6x^2 ?

The solutions to the equation 4x^2-11x+3=6x-6x^2 are x= 3/2 ,x= 1/5

Find the zeros of 4x^2-11x+3=6x-6x^2

The zeros of 4x^2-11x+3=6x-6x^2 are x= 3/2 ,x= 1/5

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4 x^{2} - 11 x + 3 = 6 x - 6 x^{2}

x = \frac{3}{2}, x = \frac{1}{5}

Decimal Notation

x = 1.5, x = 0.2

Solution steps

4 x^{2} - 11 x + 3 = 6 x - 6 x^{2}

Move

6 x^{2}

to the left side

10 x^{2} - 11 x + 3 = 6 x

Move

6 x

to the left side

10 x^{2} - 17 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 10 \cdot 3}{2 \cdot 10}

(- 17)^{2} - 4 \cdot 10 \cdot 3 = 13

x_{1, 2} = \frac{- ( - 17 ) \pm 13}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 13}{2 \cdot 10}, x_{2} = \frac{- ( - 17 ) - 13}{2 \cdot 10}

x = \frac{- ( - 17 ) + 13}{2 \cdot 10} : \frac{3}{2}

x = \frac{- ( - 17 ) - 13}{2 \cdot 10} : \frac{1}{5}

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = \frac{1}{5}

- u^{2} - 3 u + 4 = 0

20 a^{2} + 132 a + 160 = 0

(x - 1)^{2} = - 2

x^{2} + 2 x + 9

2 x^{2} + 15 = 23

What are the solutions to the equation 4x^2-11x+3=6x-6x^2 ?
The solutions to the equation 4x^2-11x+3=6x-6x^2 are x= 3/2 ,x= 1/5
Find the zeros of 4x^2-11x+3=6x-6x^2
The zeros of 4x^2-11x+3=6x-6x^2 are x= 3/2 ,x= 1/5