What are the solutions to the equation 7x^2-48x=-36 ?

The solutions to the equation 7x^2-48x=-36 are x=6,x= 6/7

Find the zeros of 7x^2-48x=-36

The zeros of 7x^2-48x=-36 are x=6,x= 6/7

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7 x^{2} - 48 x = - 36

x = 6, x = \frac{6}{7}

Decimal Notation

x = 6, x = 0.85714 \dots

Solution steps

7 x^{2} - 48 x = - 36

Move

36

to the left side

7 x^{2} - 48 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 7 \cdot 36}{2 \cdot 7}

(- 48)^{2} - 4 \cdot 7 \cdot 36 = 36

x_{1, 2} = \frac{- ( - 48 ) \pm 36}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 48 ) + 36}{2 \cdot 7}, x_{2} = \frac{- ( - 48 ) - 36}{2 \cdot 7}

x = \frac{- ( - 48 ) + 36}{2 \cdot 7} : 6

x = \frac{- ( - 48 ) - 36}{2 \cdot 7} : \frac{6}{7}

The solutions to the quadratic equation are:

x = 6, x = \frac{6}{7}

(2 x)^{2} = 2 x

4 y^{2} = 20 y

6 s^{2} + 185 = 0

9 x^{2} + 2 x + 1 = 0

3 x^{2} = 14 x + 24

What are the solutions to the equation 7x^2-48x=-36 ?
The solutions to the equation 7x^2-48x=-36 are x=6,x= 6/7
Find the zeros of 7x^2-48x=-36
The zeros of 7x^2-48x=-36 are x=6,x= 6/7