What are the solutions to the equation (7x+23)^2=27 ?

The solutions to the equation (7x+23)^2=27 are x=(3sqrt(3)-23)/7 ,x=(-3sqrt(3)-23)/7

Find the zeros of (7x+23)^2=27

The zeros of (7x+23)^2=27 are x=(3sqrt(3)-23)/7 ,x=(-3sqrt(3)-23)/7

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(7 x + 23)^{2} = 27

x = \frac{3 3 - 23}{7}, x = \frac{- 3 3 - 23}{7}

Decimal Notation

x = - 2.54340 \dots, x = - 4.02802 \dots

Solution steps

(7 x + 23)^{2} = 27

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

7 x + 23 = 27 : x = \frac{3 3 - 23}{7}

Solve

7 x + 23 = - 27 : x = \frac{- 3 3 - 23}{7}

The solutions to the quadratic equation are:

x = \frac{3 3 - 23}{7}, x = \frac{- 3 3 - 23}{7}

4 x^{2} - 16 x + 16 = 16 - 16 x

- x^{2} + 9 x + 2 = 0

x^{2} + 3 (- x) = 16

5 m (m + 3) = 10

x^{2} + 5^{2} = 7^{2}

What are the solutions to the equation (7x+23)^2=27 ?
The solutions to the equation (7x+23)^2=27 are x=(3sqrt(3)-23)/7 ,x=(-3sqrt(3)-23)/7
Find the zeros of (7x+23)^2=27
The zeros of (7x+23)^2=27 are x=(3sqrt(3)-23)/7 ,x=(-3sqrt(3)-23)/7