What are the solutions to the equation 5m(m+3)=10 ?

The solutions to the equation 5m(m+3)=10 are m=(-3+sqrt(17))/2 ,m=-(3+sqrt(17))/2

Find the zeros of 5m(m+3)=10

The zeros of 5m(m+3)=10 are m=(-3+sqrt(17))/2 ,m=-(3+sqrt(17))/2

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5 m (m + 3) = 10

m = \frac{- 3 + 17}{2}, m = - \frac{3 + 17}{2}

Decimal Notation

m = 0.56155 \dots, m = - 3.56155 \dots

Solution steps

5 m (m + 3) = 10

Expand

5 m (m + 3) : 5 m^{2} + 15 m

5 m^{2} + 15 m = 10

Move

10

to the left side

5 m^{2} + 15 m - 10 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 5 ( - 10 )}{2 \cdot 5}

1 5^{2} - 4 \cdot 5 (- 10) = 517

m_{1, 2} = \frac{- 15 \pm 5 17}{2 \cdot 5}

Separate the solutions

m_{1} = \frac{- 15 + 5 17}{2 \cdot 5}, m_{2} = \frac{- 15 - 5 17}{2 \cdot 5}

m = \frac{- 15 + 5 17}{2 \cdot 5} : \frac{- 3 + 17}{2}

m = \frac{- 15 - 5 17}{2 \cdot 5} : - \frac{3 + 17}{2}

The solutions to the quadratic equation are:

m = \frac{- 3 + 17}{2}, m = - \frac{3 + 17}{2}

x^{2} + 5^{2} = 7^{2}

t^{2} - t + 1 = 1

3 (2 - 2 x) = (x - 4) (x - 2)

x^{2} + 14 x + 40 = 0

101^{2} + x^{2} = 1 4^{2}

What are the solutions to the equation 5m(m+3)=10 ?
The solutions to the equation 5m(m+3)=10 are m=(-3+sqrt(17))/2 ,m=-(3+sqrt(17))/2
Find the zeros of 5m(m+3)=10
The zeros of 5m(m+3)=10 are m=(-3+sqrt(17))/2 ,m=-(3+sqrt(17))/2