What are the solutions to the equation sqrt(101)^2+x^2=14^2 ?

The solutions to the equation sqrt(101)^2+x^2=14^2 are x=sqrt(95),x=-sqrt(95)

Find the zeros of sqrt(101)^2+x^2=14^2

The zeros of sqrt(101)^2+x^2=14^2 are x=sqrt(95),x=-sqrt(95)

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101^{2} + x^{2} = 1 4^{2}

x = 95, x = - 95

Decimal Notation

x = 9.74679 \dots, x = - 9.74679 \dots

Solution steps

(101)^{2} + x^{2} = 1 4^{2}

Move

101^{2}

to the right side

x^{2} = 95

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 95, x = - 95

4 x^{2} + 77 = - 36

w, w^{2} + 4 w = 0

9 x - 2 - 2 x (3 x - 1) = 4 x^{2}

5 y^{2} = 7 y + 6

2 s^{2} + 15 s + 40 = 0

What are the solutions to the equation sqrt(101)^2+x^2=14^2 ?
The solutions to the equation sqrt(101)^2+x^2=14^2 are x=sqrt(95),x=-sqrt(95)
Find the zeros of sqrt(101)^2+x^2=14^2
The zeros of sqrt(101)^2+x^2=14^2 are x=sqrt(95),x=-sqrt(95)