What are the solutions to the equation solvefor w,w^2+4w=0 ?

The solutions to the equation solvefor w,w^2+4w=0 are w=0,w=-4

Find the zeros of solvefor w,w^2+4w=0

The zeros of solvefor w,w^2+4w=0 are w=0,w=-4

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w, w^{2} + 4 w = 0

w = 0, w = - 4

Solution steps

w^{2} + 4 w = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot 0 = 4

w_{1, 2} = \frac{- 4 \pm 4}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 4 + 4}{2 \cdot 1}, w_{2} = \frac{- 4 - 4}{2 \cdot 1}

w = \frac{- 4 + 4}{2 \cdot 1} : 0

w = \frac{- 4 - 4}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

w = 0, w = - 4

9 x - 2 - 2 x (3 x - 1) = 4 x^{2}

5 y^{2} = 7 y + 6

2 s^{2} + 15 s + 40 = 0

x, x^{2} + 10 x + 24 = 0

a^{2} - a - 2 = 0

What are the solutions to the equation solvefor w,w^2+4w=0 ?
The solutions to the equation solvefor w,w^2+4w=0 are w=0,w=-4
Find the zeros of solvefor w,w^2+4w=0
The zeros of solvefor w,w^2+4w=0 are w=0,w=-4