What are the solutions to the equation t^2-t+6=0 ?

The solutions to the equation t^2-t+6=0 are t= 1/2+i(sqrt(23))/2 ,t= 1/2-i(sqrt(23))/2

Find the zeros of t^2-t+6=0

The zeros of t^2-t+6=0 are t= 1/2+i(sqrt(23))/2 ,t= 1/2-i(sqrt(23))/2

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t^{2} - t + 6 = 0

t = \frac{1}{2} + i \frac{23}{2}, t = \frac{1}{2} - i \frac{23}{2}

Solution steps

t^{2} - t + 6 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

Simplify

(- 1)^{2} - 4 \cdot 1 \cdot 6 : 23 i

t_{1, 2} = \frac{- ( - 1 ) \pm 23 i}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- ( - 1 ) + 23 i}{2 \cdot 1}, t_{2} = \frac{- ( - 1 ) - 23 i}{2 \cdot 1}

t = \frac{- ( - 1 ) + 23 i}{2 \cdot 1} : \frac{1}{2} + i \frac{23}{2}

t = \frac{- ( - 1 ) - 23 i}{2 \cdot 1} : \frac{1}{2} - i \frac{23}{2}

The solutions to the quadratic equation are:

t = \frac{1}{2} + i \frac{23}{2}, t = \frac{1}{2} - i \frac{23}{2}

x^{2} + 2 x - 9 = 0

x, - 493 + 46 x - x^{2} = 0

x^{2} - 9.9 x - 312.5 = 0

E, S = \frac{E ^{2}}{Z}

8 + 4 x - x^{2}

What are the solutions to the equation t^2-t+6=0 ?
The solutions to the equation t^2-t+6=0 are t= 1/2+i(sqrt(23))/2 ,t= 1/2-i(sqrt(23))/2
Find the zeros of t^2-t+6=0
The zeros of t^2-t+6=0 are t= 1/2+i(sqrt(23))/2 ,t= 1/2-i(sqrt(23))/2