What are the solutions to the equation (1-x)*(5+2x)=5 ?

The solutions to the equation (1-x)*(5+2x)=5 are x=-3/2 ,x=0

Find the zeros of (1-x)*(5+2x)=5

The zeros of (1-x)*(5+2x)=5 are x=-3/2 ,x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(1 - x) \cdot (5 + 2 x) = 5

x = - \frac{3}{2}, x = 0

Decimal Notation

x = - 1.5, x = 0

Solution steps

(1 - x) (5 + 2 x) = 5

Expand

(1 - x) (5 + 2 x) : 5 - 3 x - 2 x^{2}

5 - 3 x - 2 x^{2} = 5

Move

5

to the left side

- 2 x^{2} - 3 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

(- 3)^{2} - 4 (- 2) \cdot 0 = 3

x_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3}{2 ( - 2 )}, x_{2} = \frac{- ( - 3 ) - 3}{2 ( - 2 )}

x = \frac{- ( - 3 ) + 3}{2 ( - 2 )} : - \frac{3}{2}

x = \frac{- ( - 3 ) - 3}{2 ( - 2 )} : 0

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = 0

3 u^{2} + 11 u = - 6

2 x^{2} = - 5 x - 2

x^{2} + 14 x + 44 = 0

x^{2} - 4 x = 33

2 x^{2} + 3 = - 29

What are the solutions to the equation (1-x)*(5+2x)=5 ?
The solutions to the equation (1-x)*(5+2x)=5 are x=-3/2 ,x=0
Find the zeros of (1-x)*(5+2x)=5
The zeros of (1-x)*(5+2x)=5 are x=-3/2 ,x=0