What are the solutions to the equation factor 12x^2+8=20x ?

The solutions to the equation factor 12x^2+8=20x are x= 2/3 ,x=1

Find the zeros of factor 12x^2+8=20x

The zeros of factor 12x^2+8=20x are x= 2/3 ,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

12 x^{2} + 8 = 20 x

x = \frac{2}{3}, x = 1

Decimal Notation

x = 0.66666 \dots, x = 1

Solution steps

12 x^{2} + 8 = 20 x

Move

20 x

to the left side

12 x^{2} + 8 - 20 x = 0

Write in the standard form

a x^{2} + b x + c = 0

12 x^{2} - 20 x + 8 = 0

Factor

12 x^{2} - 20 x + 8 : 4 (3 x - 2) (x - 1)

4 (3 x - 2) (x - 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 2 = 0 or x - 1 = 0

Solve

3 x - 2 = 0 : x = \frac{2}{3}

Solve

x - 1 = 0 : x = 1

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = 1

3 t^{2} - 12 t - 36 = 0

(x) = 50000 + 200 x + 0.3 x^{2}

x (x - 1) = x + 3

9 x^{2} - 18 x + 3

2 x - x^{2} = 2 - x

What are the solutions to the equation factor 12x^2+8=20x ?
The solutions to the equation factor 12x^2+8=20x are x= 2/3 ,x=1
Find the zeros of factor 12x^2+8=20x
The zeros of factor 12x^2+8=20x are x= 2/3 ,x=1