What are the solutions to the equation 3x^2-96x-92=0 ?

The solutions to the equation 3x^2-96x-92=0 are x=(2(24+sqrt(645)))/3 ,x=(2(24-sqrt(645)))/3

Find the zeros of 3x^2-96x-92=0

The zeros of 3x^2-96x-92=0 are x=(2(24+sqrt(645)))/3 ,x=(2(24-sqrt(645)))/3

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3 x^{2} - 96 x - 92 = 0

x = \frac{2 ( 24 + 645 )}{3}, x = \frac{2 ( 24 - 645 )}{3}

Decimal Notation

x = 32.93123 \dots, x = - 0.93123 \dots

Solution steps

3 x^{2} - 96 x - 92 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 96 ) \pm ( - 96 ) ^{2} - 4 \cdot 3 ( - 92 )}{2 \cdot 3}

(- 96)^{2} - 4 \cdot 3 (- 92) = 4645

x_{1, 2} = \frac{- ( - 96 ) \pm 4 645}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 96 ) + 4 645}{2 \cdot 3}, x_{2} = \frac{- ( - 96 ) - 4 645}{2 \cdot 3}

x = \frac{- ( - 96 ) + 4 645}{2 \cdot 3} : \frac{2 ( 24 + 645 )}{3}

x = \frac{- ( - 96 ) - 4 645}{2 \cdot 3} : \frac{2 ( 24 - 645 )}{3}

The solutions to the quadratic equation are:

x = \frac{2 ( 24 + 645 )}{3}, x = \frac{2 ( 24 - 645 )}{3}

x^{2} + 20 x + 5

x (400 - x) = 10000

12 = x (x + 3)

k^{2} - 2 k - 8 = 0

(4 - x)^{2} = 0

What are the solutions to the equation 3x^2-96x-92=0 ?
The solutions to the equation 3x^2-96x-92=0 are x=(2(24+sqrt(645)))/3 ,x=(2(24-sqrt(645)))/3
Find the zeros of 3x^2-96x-92=0
The zeros of 3x^2-96x-92=0 are x=(2(24+sqrt(645)))/3 ,x=(2(24-sqrt(645)))/3