What are the solutions to the equation 12=x(x+3) ?

The solutions to the equation 12=x(x+3) are x=(-3+sqrt(57))/2 ,x=(-3-sqrt(57))/2

Find the zeros of 12=x(x+3)

The zeros of 12=x(x+3) are x=(-3+sqrt(57))/2 ,x=(-3-sqrt(57))/2

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12 = x (x + 3)

x = \frac{- 3 + 57}{2}, x = \frac{- 3 - 57}{2}

Decimal Notation

x = 2.27491 \dots, x = - 5.27491 \dots

Solution steps

12 = x (x + 3)

Expand

x (x + 3) : x^{2} + 3 x

12 = x^{2} + 3 x

Switch sides

x^{2} + 3 x = 12

Move

12

to the left side

x^{2} + 3 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - 12 )}{2 \cdot 1}

3^{2} - 4 \cdot 1 \cdot (- 12) = 57

x_{1, 2} = \frac{- 3 \pm 57}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 3 + 57}{2 \cdot 1}, x_{2} = \frac{- 3 - 57}{2 \cdot 1}

x = \frac{- 3 + 57}{2 \cdot 1} : \frac{- 3 + 57}{2}

x = \frac{- 3 - 57}{2 \cdot 1} : \frac{- 3 - 57}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 57}{2}, x = \frac{- 3 - 57}{2}

k^{2} - 2 k - 8 = 0

(4 - x)^{2} = 0

x^{2} + \frac{3}{2} x = 1

2 v^{2} - 9 = 3 v

2 x^{2} - 48 x + 126 = 0

What are the solutions to the equation 12=x(x+3) ?
The solutions to the equation 12=x(x+3) are x=(-3+sqrt(57))/2 ,x=(-3-sqrt(57))/2
Find the zeros of 12=x(x+3)
The zeros of 12=x(x+3) are x=(-3+sqrt(57))/2 ,x=(-3-sqrt(57))/2