What are the solutions to the equation 2v^2-9=3v ?

The solutions to the equation 2v^2-9=3v are v=3,v=-3/2

Find the zeros of 2v^2-9=3v

The zeros of 2v^2-9=3v are v=3,v=-3/2

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2 v^{2} - 9 = 3 v

v = 3, v = - \frac{3}{2}

Decimal Notation

v = 3, v = - 1.5

Solution steps

2 v^{2} - 9 = 3 v

Move

3 v

to the left side

2 v^{2} - 9 - 3 v = 0

Write in the standard form

a x^{2} + b x + c = 0

2 v^{2} - 3 v - 9 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 ( - 9 )}{2 \cdot 2}

(- 3)^{2} - 4 \cdot 2 (- 9) = 9

v_{1, 2} = \frac{- ( - 3 ) \pm 9}{2 \cdot 2}

Separate the solutions

v_{1} = \frac{- ( - 3 ) + 9}{2 \cdot 2}, v_{2} = \frac{- ( - 3 ) - 9}{2 \cdot 2}

v = \frac{- ( - 3 ) + 9}{2 \cdot 2} : 3

v = \frac{- ( - 3 ) - 9}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

v = 3, v = - \frac{3}{2}

2 x^{2} - 48 x + 126 = 0

5 x^{2} + 3 x = 36

x = 2 x^{2} - 12 x + 25

0.02 x^{2} + 2 x - 40 = 0

m^{2} - 8 m = 20

What are the solutions to the equation 2v^2-9=3v ?
The solutions to the equation 2v^2-9=3v are v=3,v=-3/2
Find the zeros of 2v^2-9=3v
The zeros of 2v^2-9=3v are v=3,v=-3/2