What are the solutions to the equation D^2-2D+2=0 ?

The solutions to the equation D^2-2D+2=0 are D=1+i,D=1-i

Find the zeros of D^2-2D+2=0

The zeros of D^2-2D+2=0 are D=1+i,D=1-i

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D^{2} - 2 D + 2 = 0

D = 1 + i, D = 1 - i

Solution steps

D^{2} - 2 D + 2 = 0

Solve with the quadratic formula

D_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 2 : 2 i

D_{1, 2} = \frac{- ( - 2 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

D_{1} = \frac{- ( - 2 ) + 2 i}{2 \cdot 1}, D_{2} = \frac{- ( - 2 ) - 2 i}{2 \cdot 1}

D = \frac{- ( - 2 ) + 2 i}{2 \cdot 1} : 1 + i

D = \frac{- ( - 2 ) - 2 i}{2 \cdot 1} : 1 - i

The solutions to the quadratic equation are:

D = 1 + i, D = 1 - i

x, x^{2} + y^{2} + 2 x y = 25

4 x^{2} - 6 x = 0

64 x^{2} - 64 x + 16 = 0

c^{2} + 2 c = 48

y^{2} + 21 y = 0

What are the solutions to the equation D^2-2D+2=0 ?
The solutions to the equation D^2-2D+2=0 are D=1+i,D=1-i
Find the zeros of D^2-2D+2=0
The zeros of D^2-2D+2=0 are D=1+i,D=1-i