What are the solutions to the equation y^2+21y=0 ?

The solutions to the equation y^2+21y=0 are y=0,y=-21

Find the zeros of y^2+21y=0

The zeros of y^2+21y=0 are y=0,y=-21

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y^{2} + 21 y = 0

y = 0, y = - 21

Solution steps

y^{2} + 21 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 21 \pm 2 1 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

2 1^{2} - 4 \cdot 1 \cdot 0 = 21

y_{1, 2} = \frac{- 21 \pm 21}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 21 + 21}{2 \cdot 1}, y_{2} = \frac{- 21 - 21}{2 \cdot 1}

y = \frac{- 21 + 21}{2 \cdot 1} : 0

y = \frac{- 21 - 21}{2 \cdot 1} : - 21

The solutions to the quadratic equation are:

y = 0, y = - 21

5 x^{2} - 18 = 587

2 y^{2} - y + 5 = 0

7 p^{2} = - 3 + 5 p

2 x^{2} + 12 x = 9

(x) = 120 x - 40 x^{2}

What are the solutions to the equation y^2+21y=0 ?
The solutions to the equation y^2+21y=0 are y=0,y=-21
Find the zeros of y^2+21y=0
The zeros of y^2+21y=0 are y=0,y=-21