What are the solutions to the equation (x)=120x-40x^2 ?

The solutions to the equation (x)=120x-40x^2 are x=0,x= 119/40

Find the zeros of (x)=120x-40x^2

The zeros of (x)=120x-40x^2 are x=0,x= 119/40

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(x) = 120 x - 40 x^{2}

x = 0, x = \frac{119}{40}

Decimal Notation

x = 0, x = 2.975

Solution steps

(x) = 120 x - 40 x^{2}

Refine

x = 120 x - 40 x^{2}

Switch sides

120 x - 40 x^{2} = x

Move

x

to the left side

- 40 x^{2} + 119 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 119 \pm 11 9 ^{2} - 4 ( - 40 ) \cdot 0}{2 ( - 40 )}

11 9^{2} - 4 (- 40) \cdot 0 = 119

x_{1, 2} = \frac{- 119 \pm 119}{2 ( - 40 )}

Separate the solutions

x_{1} = \frac{- 119 + 119}{2 ( - 40 )}, x_{2} = \frac{- 119 - 119}{2 ( - 40 )}

x = \frac{- 119 + 119}{2 ( - 40 )} : 0

x = \frac{- 119 - 119}{2 ( - 40 )} : \frac{119}{40}

The solutions to the quadratic equation are:

x = 0, x = \frac{119}{40}

X^{2} - 9 X + 14 = 0

2 y^{2} - y + 6 = 0

a^{2} - 12 a = - 27

4 x^{2} + 232 = - 64 x

- 16 x^{2} + 12 x + 40 = 0

What are the solutions to the equation (x)=120x-40x^2 ?
The solutions to the equation (x)=120x-40x^2 are x=0,x= 119/40
Find the zeros of (x)=120x-40x^2
The zeros of (x)=120x-40x^2 are x=0,x= 119/40