What are the solutions to the equation y^2-5=8y ?

The solutions to the equation y^2-5=8y are y=4+sqrt(21),y=4-sqrt(21)

Find the zeros of y^2-5=8y

The zeros of y^2-5=8y are y=4+sqrt(21),y=4-sqrt(21)

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y^{2} - 5 = 8 y

y = 4 + 21, y = 4 - 21

Decimal Notation

y = 8.58257 \dots, y = - 0.58257 \dots

Solution steps

y^{2} - 5 = 8 y

Move

8 y

to the left side

y^{2} - 5 - 8 y = 0

Write in the standard form

a x^{2} + b x + c = 0

y^{2} - 8 y - 5 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 5) = 221

y_{1, 2} = \frac{- ( - 8 ) \pm 2 21}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 8 ) + 2 21}{2 \cdot 1}, y_{2} = \frac{- ( - 8 ) - 2 21}{2 \cdot 1}

y = \frac{- ( - 8 ) + 2 21}{2 \cdot 1} : 4 + 21

y = \frac{- ( - 8 ) - 2 21}{2 \cdot 1} : 4 - 21

The solutions to the quadratic equation are:

y = 4 + 21, y = 4 - 21

x, 3 x^{2} + 2 y^{2} = c

- 12 r^{2} - 2 = - 4 r

0.825 x^{2} + 0.15 x - 0.003621753 = 0

x, f (x + c) = 8 (x + c)^{2} + 4

49 k^{2} - 231 k - 70 = 0

What are the solutions to the equation y^2-5=8y ?
The solutions to the equation y^2-5=8y are y=4+sqrt(21),y=4-sqrt(21)
Find the zeros of y^2-5=8y
The zeros of y^2-5=8y are y=4+sqrt(21),y=4-sqrt(21)