What are the solutions to the equation 49k^2-231k-70=0 ?

The solutions to the equation 49k^2-231k-70=0 are k=5,k=-2/7

Find the zeros of 49k^2-231k-70=0

The zeros of 49k^2-231k-70=0 are k=5,k=-2/7

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49 k^{2} - 231 k - 70 = 0

k = 5, k = - \frac{2}{7}

Decimal Notation

k = 5, k = - 0.28571 \dots

Solution steps

49 k^{2} - 231 k - 70 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 231 ) \pm ( - 231 ) ^{2} - 4 \cdot 49 ( - 70 )}{2 \cdot 49}

(- 231)^{2} - 4 \cdot 49 (- 70) = 259

k_{1, 2} = \frac{- ( - 231 ) \pm 259}{2 \cdot 49}

Separate the solutions

k_{1} = \frac{- ( - 231 ) + 259}{2 \cdot 49}, k_{2} = \frac{- ( - 231 ) - 259}{2 \cdot 49}

k = \frac{- ( - 231 ) + 259}{2 \cdot 49} : 5

k = \frac{- ( - 231 ) - 259}{2 \cdot 49} : - \frac{2}{7}

The solutions to the quadratic equation are:

k = 5, k = - \frac{2}{7}

a x^{2} + a x + 7 = 3 x^{2} - x + 5 a

mn x^{2} - (m^{2} - n^{2}) x + mn = 0

5 x^{2} + 7 x - 8 = 0

0 = 2 x^{2} - x + 3

(x - 2) \cdot (x - 5) = 0

What are the solutions to the equation 49k^2-231k-70=0 ?
The solutions to the equation 49k^2-231k-70=0 are k=5,k=-2/7
Find the zeros of 49k^2-231k-70=0
The zeros of 49k^2-231k-70=0 are k=5,k=-2/7