What are the solutions to the equation 5t^2-11t=12 ?

The solutions to the equation 5t^2-11t=12 are t=3,t=-4/5

Find the zeros of 5t^2-11t=12

The zeros of 5t^2-11t=12 are t=3,t=-4/5

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5 t^{2} - 11 t = 12

t = 3, t = - \frac{4}{5}

Decimal Notation

t = 3, t = - 0.8

Solution steps

5 t^{2} - 11 t = 12

Move

12

to the left side

5 t^{2} - 11 t - 12 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 5 ( - 12 )}{2 \cdot 5}

(- 11)^{2} - 4 \cdot 5 (- 12) = 19

t_{1, 2} = \frac{- ( - 11 ) \pm 19}{2 \cdot 5}

Separate the solutions

t_{1} = \frac{- ( - 11 ) + 19}{2 \cdot 5}, t_{2} = \frac{- ( - 11 ) - 19}{2 \cdot 5}

t = \frac{- ( - 11 ) + 19}{2 \cdot 5} : 3

t = \frac{- ( - 11 ) - 19}{2 \cdot 5} : - \frac{4}{5}

The solutions to the quadratic equation are:

t = 3, t = - \frac{4}{5}

x + 3 x + 1.5 x 44 x - 2 = 169

7 x^{2} + 54 x - 16 = 0

6 n^{2} + 40 = 70

n^{2} = - 3 n + 40

7 (x^{2} - 4) = 4 (x^{2} - 5)

What are the solutions to the equation 5t^2-11t=12 ?
The solutions to the equation 5t^2-11t=12 are t=3,t=-4/5
Find the zeros of 5t^2-11t=12
The zeros of 5t^2-11t=12 are t=3,t=-4/5