What are the solutions to the equation x+3x+1.5x44x-2=169 ?

The solutions to the equation x+3x+1.5x44x-2=169 are x=(-2+sqrt(11290))/(66),x=-(2+sqrt(11290))/(66)

Find the zeros of x+3x+1.5x44x-2=169

The zeros of x+3x+1.5x44x-2=169 are x=(-2+sqrt(11290))/(66),x=-(2+sqrt(11290))/(66)

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x + 3 x + 1.5 x 44 x - 2 = 169

x = \frac{- 2 + 11290}{66}, x = - \frac{2 + 11290}{66}

Decimal Notation

x = 1.57961 \dots, x = - 1.64021 \dots

Solution steps

x + 3 x + 1.5 x \cdot 44 x - 2 = 169

Expand

x + 3 x + 1.5 x \cdot 44 x - 2 : 4 x + 66 x^{2} - 2

4 x + 66 x^{2} - 2 = 169

Move

169

to the left side

66 x^{2} + 4 x - 171 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 66 ( - 171 )}{2 \cdot 66}

4^{2} - 4 \cdot 66 (- 171) = 211290

x_{1, 2} = \frac{- 4 \pm 2 11290}{2 \cdot 66}

Separate the solutions

x_{1} = \frac{- 4 + 2 11290}{2 \cdot 66}, x_{2} = \frac{- 4 - 2 11290}{2 \cdot 66}

x = \frac{- 4 + 2 11290}{2 \cdot 66} : \frac{- 2 + 11290}{66}

x = \frac{- 4 - 2 11290}{2 \cdot 66} : - \frac{2 + 11290}{66}

The solutions to the quadratic equation are:

x = \frac{- 2 + 11290}{66}, x = - \frac{2 + 11290}{66}

7 x^{2} + 54 x - 16 = 0

6 n^{2} + 40 = 70

n^{2} = - 3 n + 40

7 (x^{2} - 4) = 4 (x^{2} - 5)

7 j^{2} - 3 j = - j + 9

What are the solutions to the equation x+3x+1.5x44x-2=169 ?
The solutions to the equation x+3x+1.5x44x-2=169 are x=(-2+sqrt(11290))/(66),x=-(2+sqrt(11290))/(66)
Find the zeros of x+3x+1.5x44x-2=169
The zeros of x+3x+1.5x44x-2=169 are x=(-2+sqrt(11290))/(66),x=-(2+sqrt(11290))/(66)