What are the solutions to the equation -12=-20x^2+56x ?

The solutions to the equation -12=-20x^2+56x are x=-1/5 ,x=3

Find the zeros of -12=-20x^2+56x

The zeros of -12=-20x^2+56x are x=-1/5 ,x=3

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- 12 = - 20 x^{2} + 56 x

x = - \frac{1}{5}, x = 3

Decimal Notation

x = - 0.2, x = 3

Solution steps

- 12 = - 20 x^{2} + 56 x

Switch sides

- 20 x^{2} + 56 x = - 12

Move

12

to the left side

- 20 x^{2} + 56 x + 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 56 \pm 5 6 ^{2} - 4 ( - 20 ) \cdot 12}{2 ( - 20 )}

5 6^{2} - 4 (- 20) \cdot 12 = 64

x_{1, 2} = \frac{- 56 \pm 64}{2 ( - 20 )}

Separate the solutions

x_{1} = \frac{- 56 + 64}{2 ( - 20 )}, x_{2} = \frac{- 56 - 64}{2 ( - 20 )}

x = \frac{- 56 + 64}{2 ( - 20 )} : - \frac{1}{5}

x = \frac{- 56 - 64}{2 ( - 20 )} : 3

The solutions to the quadratic equation are:

x = - \frac{1}{5}, x = 3

x = 5 \cdot x^{2}

- x^{2} + 10 x - 12 = 0

500 x^{2} - 60 x = 141.33

A = π (\frac{d}{2})^{2}

4 v^{2} - 5 v - 9 = 0

What are the solutions to the equation -12=-20x^2+56x ?
The solutions to the equation -12=-20x^2+56x are x=-1/5 ,x=3
Find the zeros of -12=-20x^2+56x
The zeros of -12=-20x^2+56x are x=-1/5 ,x=3