What are the solutions to the equation 4v^2-5v-9=0 ?

The solutions to the equation 4v^2-5v-9=0 are v= 9/4 ,v=-1

Find the zeros of 4v^2-5v-9=0

The zeros of 4v^2-5v-9=0 are v= 9/4 ,v=-1

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4 v^{2} - 5 v - 9 = 0

v = \frac{9}{4}, v = - 1

Decimal Notation

v = 2.25, v = - 1

Solution steps

4 v^{2} - 5 v - 9 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 ( - 9 )}{2 \cdot 4}

(- 5)^{2} - 4 \cdot 4 (- 9) = 13

v_{1, 2} = \frac{- ( - 5 ) \pm 13}{2 \cdot 4}

Separate the solutions

v_{1} = \frac{- ( - 5 ) + 13}{2 \cdot 4}, v_{2} = \frac{- ( - 5 ) - 13}{2 \cdot 4}

v = \frac{- ( - 5 ) + 13}{2 \cdot 4} : \frac{9}{4}

v = \frac{- ( - 5 ) - 13}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

v = \frac{9}{4}, v = - 1

5 x^{2} + 32 = 57

3 x^{2} - 6 x - 246 = 0

4.2 x + 8.6 + (- 3.3) x^{2} = 0

3 x^{2} - 45 x + 168 = 0

x^{2} + 4 x + 3 = 1

What are the solutions to the equation 4v^2-5v-9=0 ?
The solutions to the equation 4v^2-5v-9=0 are v= 9/4 ,v=-1
Find the zeros of 4v^2-5v-9=0
The zeros of 4v^2-5v-9=0 are v= 9/4 ,v=-1