What are the solutions to the equation 6x^2=x^2+11 ?

The solutions to the equation 6x^2=x^2+11 are x=sqrt(11/5),x=-sqrt(11/5)

Find the zeros of 6x^2=x^2+11

The zeros of 6x^2=x^2+11 are x=sqrt(11/5),x=-sqrt(11/5)

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6 x^{2} = x^{2} + 11

x = \frac{11}{5}, x = - \frac{11}{5}

Decimal Notation

x = 1.48323 \dots, x = - 1.48323 \dots

Solution steps

6 x^{2} = x^{2} + 11

Move

x^{2}

to the left side

5 x^{2} = 11

Divide both sides by

5

x^{2} = \frac{11}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{11}{5}, x = - \frac{11}{5}

- x^{2} - 5 x + 10 = 0

x^{2} + 2 x - 18

x^{2} (- 8 b + 7) = - 8 b + 6

x, x (x - 5) = 0

0 = 40 - 10 t - 5 t^{2}

What are the solutions to the equation 6x^2=x^2+11 ?
The solutions to the equation 6x^2=x^2+11 are x=sqrt(11/5),x=-sqrt(11/5)
Find the zeros of 6x^2=x^2+11
The zeros of 6x^2=x^2+11 are x=sqrt(11/5),x=-sqrt(11/5)