What are the solutions to the equation -x^2+10x=x+18 ?

The solutions to the equation -x^2+10x=x+18 are x=3,x=6

Find the zeros of -x^2+10x=x+18

The zeros of -x^2+10x=x+18 are x=3,x=6

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- x^{2} + 10 x = x + 18

x = 3, x = 6

Solution steps

- x^{2} + 10 x = x + 18

Move

18

to the left side

- x^{2} + 10 x - 18 = x

Move

x

to the left side

- x^{2} + 9 x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 1 ) ( - 18 )}{2 ( - 1 )}

9^{2} - 4 (- 1) (- 18) = 3

x_{1, 2} = \frac{- 9 \pm 3}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 9 + 3}{2 ( - 1 )}, x_{2} = \frac{- 9 - 3}{2 ( - 1 )}

x = \frac{- 9 + 3}{2 ( - 1 )} : 3

x = \frac{- 9 - 3}{2 ( - 1 )} : 6

The solutions to the quadratic equation are:

x = 3, x = 6

13 x^{2} - 12 x - 2 = 0

49 t^{2} = 4

x^{2} - 5 x - 48 = 0

a + g (a) = - x^{2} + 4 x

(y + 1)^{2} = 16

What are the solutions to the equation -x^2+10x=x+18 ?
The solutions to the equation -x^2+10x=x+18 are x=3,x=6
Find the zeros of -x^2+10x=x+18
The zeros of -x^2+10x=x+18 are x=3,x=6