What are the solutions to the equation x^2-4x+9=14 ?

The solutions to the equation x^2-4x+9=14 are x=5,x=-1

Find the zeros of x^2-4x+9=14

The zeros of x^2-4x+9=14 are x=5,x=-1

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x^{2} - 4 x + 9 = 14

x = 5, x = - 1

Solution steps

x^{2} - 4 x + 9 = 14

Move

14

to the left side

x^{2} - 4 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 5) = 6

x_{1, 2} = \frac{- ( - 4 ) \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 6}{2 \cdot 1}

x = \frac{- ( - 4 ) + 6}{2 \cdot 1} : 5

x = \frac{- ( - 4 ) - 6}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 5, x = - 1

6 1^{2} = 6 0^{2} + x^{2}

5 b^{2} - 16 b = 16

x, x^{2} + y^{2} - 4 y + 7 = 0

3 + 81 n^{2} = 39

(n + 1) (x^{2} + 3 x) = (5 x + 2) (n - 1)

What are the solutions to the equation x^2-4x+9=14 ?
The solutions to the equation x^2-4x+9=14 are x=5,x=-1
Find the zeros of x^2-4x+9=14
The zeros of x^2-4x+9=14 are x=5,x=-1