What are the solutions to the equation 3+81n^2=39 ?

The solutions to the equation 3+81n^2=39 are n= 2/3 ,n=-2/3

Find the zeros of 3+81n^2=39

The zeros of 3+81n^2=39 are n= 2/3 ,n=-2/3

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3 + 81 n^{2} = 39

n = \frac{2}{3}, n = - \frac{2}{3}

Decimal Notation

n = 0.66666 \dots, n = - 0.66666 \dots

Solution steps

3 + 81 n^{2} = 39

Move

3

to the right side

81 n^{2} = 36

Divide both sides by

81

n^{2} = \frac{4}{9}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

n = \frac{4}{9}, n = - \frac{4}{9}

\frac{4}{9} = \frac{2}{3}

- \frac{4}{9} = - \frac{2}{3}

n = \frac{2}{3}, n = - \frac{2}{3}

(n + 1) (x^{2} + 3 x) = (5 x + 2) (n - 1)

7 x^{2} - 12 x = 6

x^{2} = 22 x

x^{2} = 40 x

0 = 24 - 6 x^{2}

What are the solutions to the equation 3+81n^2=39 ?
The solutions to the equation 3+81n^2=39 are n= 2/3 ,n=-2/3
Find the zeros of 3+81n^2=39
The zeros of 3+81n^2=39 are n= 2/3 ,n=-2/3