What are the solutions to the equation x^2=40x ?

The solutions to the equation x^2=40x are x=40,x=0

Find the zeros of x^2=40x

The zeros of x^2=40x are x=40,x=0

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x^{2} = 40 x

x = 40, x = 0

Solution steps

x^{2} = 40 x

Move

40 x

to the left side

x^{2} - 40 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 40)^{2} - 4 \cdot 1 \cdot 0 = 40

x_{1, 2} = \frac{- ( - 40 ) \pm 40}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 40}{2 \cdot 1}, x_{2} = \frac{- ( - 40 ) - 40}{2 \cdot 1}

x = \frac{- ( - 40 ) + 40}{2 \cdot 1} : 40

x = \frac{- ( - 40 ) - 40}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 40, x = 0

0 = 24 - 6 x^{2}

16 x (4 x - 3) = - 9

2 (x^{2} - 4) + 3 (x^{2} + 5) = 8 x - 3

15 a^{2} + 18 a + 3 = 4 a

x, y^{2} = 3 (x - h)^{2}

What are the solutions to the equation x^2=40x ?
The solutions to the equation x^2=40x are x=40,x=0
Find the zeros of x^2=40x
The zeros of x^2=40x are x=40,x=0