What are the solutions to the equation m^2-m-20=0 ?

The solutions to the equation m^2-m-20=0 are m=5,m=-4

Find the zeros of m^2-m-20=0

The zeros of m^2-m-20=0 are m=5,m=-4

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m^{2} - m - 20 = 0

m = 5, m = - 4

Solution steps

m^{2} - m - 20 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 20) = 9

m_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 1}, m_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 1}

m = \frac{- ( - 1 ) + 9}{2 \cdot 1} : 5

m = \frac{- ( - 1 ) - 9}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

m = 5, m = - 4

x^{2} + 5 x^{2} = - 4

(12 t^{2} - 10 t + 5) + (10 t - 15) = 0

x, x^{2} + x y = 20 x

x, x^{2} + x y = 20 y

x = y^{2}, y

What are the solutions to the equation m^2-m-20=0 ?
The solutions to the equation m^2-m-20=0 are m=5,m=-4
Find the zeros of m^2-m-20=0
The zeros of m^2-m-20=0 are m=5,m=-4