What are the solutions to the equation 0=4x^2+16x ?

The solutions to the equation 0=4x^2+16x are x=0,x=-4

Find the zeros of 0=4x^2+16x

The zeros of 0=4x^2+16x are x=0,x=-4

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0 = 4 x^{2} + 16 x

x = 0, x = - 4

Solution steps

0 = 4 x^{2} + 16 x

Switch sides

4 x^{2} + 16 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

1 6^{2} - 4 \cdot 4 \cdot 0 = 16

x_{1, 2} = \frac{- 16 \pm 16}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 16 + 16}{2 \cdot 4}, x_{2} = \frac{- 16 - 16}{2 \cdot 4}

x = \frac{- 16 + 16}{2 \cdot 4} : 0

x = \frac{- 16 - 16}{2 \cdot 4} : - 4

The solutions to the quadratic equation are:

x = 0, x = - 4

2 x^{2} + x = \frac{1}{2}

3 x^{2} - 507 = 0

5 y^{2} = 25

5 y^{2} = 29

x^{2} = 20 - 8 x

What are the solutions to the equation 0=4x^2+16x ?
The solutions to the equation 0=4x^2+16x are x=0,x=-4
Find the zeros of 0=4x^2+16x
The zeros of 0=4x^2+16x are x=0,x=-4