What are the solutions to the equation 11.48=-0.5x^2+0.5x+15 ?

The solutions to the equation 11.48=-0.5x^2+0.5x+15 are x=-11/5 ,x= 16/5

Find the zeros of 11.48=-0.5x^2+0.5x+15

The zeros of 11.48=-0.5x^2+0.5x+15 are x=-11/5 ,x= 16/5

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11.48 = - 0.5 x^{2} + 0.5 x + 15

x = - \frac{11}{5}, x = \frac{16}{5}

Decimal Notation

x = - 2.2, x = 3.2

Solution steps

11.48 = - 0.5 x^{2} + 0.5 x + 15

Multiply both sides by

100

1148 = - 50 x^{2} + 50 x + 1500

Switch sides

- 50 x^{2} + 50 x + 1500 = 1148

Move

1148

to the left side

- 50 x^{2} + 50 x + 352 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 ( - 50 ) \cdot 352}{2 ( - 50 )}

5 0^{2} - 4 (- 50) \cdot 352 = 270

x_{1, 2} = \frac{- 50 \pm 270}{2 ( - 50 )}

Separate the solutions

x_{1} = \frac{- 50 + 270}{2 ( - 50 )}, x_{2} = \frac{- 50 - 270}{2 ( - 50 )}

x = \frac{- 50 + 270}{2 ( - 50 )} : - \frac{11}{5}

x = \frac{- 50 - 270}{2 ( - 50 )} : \frac{16}{5}

The solutions to the quadratic equation are:

x = - \frac{11}{5}, x = \frac{16}{5}

x (18 - 2 x) = 40

5 x^{2} = 4 x - 5

5 x^{2} = 4 x + 3

a, S = 2 π a^{2} + 2 πah

12 x^{2} + 5 x - 4 = 0

What are the solutions to the equation 11.48=-0.5x^2+0.5x+15 ?
The solutions to the equation 11.48=-0.5x^2+0.5x+15 are x=-11/5 ,x= 16/5
Find the zeros of 11.48=-0.5x^2+0.5x+15
The zeros of 11.48=-0.5x^2+0.5x+15 are x=-11/5 ,x= 16/5