What are the solutions to the equation x(18-2x)=40 ?

The solutions to the equation x(18-2x)=40 are x=4,x=5

Find the zeros of x(18-2x)=40

The zeros of x(18-2x)=40 are x=4,x=5

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x (18 - 2 x) = 40

x = 4, x = 5

Solution steps

x (18 - 2 x) = 40

Expand

x (18 - 2 x) : 18 x - 2 x^{2}

18 x - 2 x^{2} = 40

Move

40

to the left side

18 x - 2 x^{2} - 40 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 2 x^{2} + 18 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 ( - 2 ) ( - 40 )}{2 ( - 2 )}

1 8^{2} - 4 (- 2) (- 40) = 2

x_{1, 2} = \frac{- 18 \pm 2}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 18 + 2}{2 ( - 2 )}, x_{2} = \frac{- 18 - 2}{2 ( - 2 )}

x = \frac{- 18 + 2}{2 ( - 2 )} : 4

x = \frac{- 18 - 2}{2 ( - 2 )} : 5

The solutions to the quadratic equation are:

x = 4, x = 5

5 x^{2} = 4 x - 5

5 x^{2} = 4 x + 3

a, S = 2 π a^{2} + 2 πah

12 x^{2} + 5 x - 4 = 0

0 = - x^{2} + 100 x

What are the solutions to the equation x(18-2x)=40 ?
The solutions to the equation x(18-2x)=40 are x=4,x=5
Find the zeros of x(18-2x)=40
The zeros of x(18-2x)=40 are x=4,x=5