What are the solutions to the equation 0=-x^2+100x ?

The solutions to the equation 0=-x^2+100x are x=0,x=100

Find the zeros of 0=-x^2+100x

The zeros of 0=-x^2+100x are x=0,x=100

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0 = - x^{2} + 100 x

x = 0, x = 100

Solution steps

0 = - x^{2} + 100 x

Switch sides

- x^{2} + 100 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 100 \pm 10 0 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

10 0^{2} - 4 (- 1) \cdot 0 = 100

x_{1, 2} = \frac{- 100 \pm 100}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 100 + 100}{2 ( - 1 )}, x_{2} = \frac{- 100 - 100}{2 ( - 1 )}

x = \frac{- 100 + 100}{2 ( - 1 )} : 0

x = \frac{- 100 - 100}{2 ( - 1 )} : 100

The solutions to the quadratic equation are:

x = 0, x = 100

4 x^{2} - 9 = 2 x^{2} + 41

- 4 x^{2} + 16 x + 5 = 0

5 u^{2} + u = 4

z^{2} + 6 z = r^{2} - 9

X^{2} = 4^{2} + 1 6^{2}

What are the solutions to the equation 0=-x^2+100x ?
The solutions to the equation 0=-x^2+100x are x=0,x=100
Find the zeros of 0=-x^2+100x
The zeros of 0=-x^2+100x are x=0,x=100