What are the solutions to the equation -4x^2+16x+5=0 ?

The solutions to the equation -4x^2+16x+5=0 are x=-(-4+sqrt(21))/2 ,x=(4+sqrt(21))/2

Find the zeros of -4x^2+16x+5=0

The zeros of -4x^2+16x+5=0 are x=-(-4+sqrt(21))/2 ,x=(4+sqrt(21))/2

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- 4 x^{2} + 16 x + 5 = 0

x = - \frac{- 4 + 21}{2}, x = \frac{4 + 21}{2}

Decimal Notation

x = - 0.29128 \dots, x = 4.29128 \dots

Solution steps

- 4 x^{2} + 16 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 4 ) \cdot 5}{2 ( - 4 )}

1 6^{2} - 4 (- 4) \cdot 5 = 421

x_{1, 2} = \frac{- 16 \pm 4 21}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 16 + 4 21}{2 ( - 4 )}, x_{2} = \frac{- 16 - 4 21}{2 ( - 4 )}

x = \frac{- 16 + 4 21}{2 ( - 4 )} : - \frac{- 4 + 21}{2}

x = \frac{- 16 - 4 21}{2 ( - 4 )} : \frac{4 + 21}{2}

The solutions to the quadratic equation are:

x = - \frac{- 4 + 21}{2}, x = \frac{4 + 21}{2}

5 u^{2} + u = 4

z^{2} + 6 z = r^{2} - 9

X^{2} = 4^{2} + 1 6^{2}

s^{2} - 14 s + 53

2 X (X - 1) = 4 X - 3

What are the solutions to the equation -4x^2+16x+5=0 ?
The solutions to the equation -4x^2+16x+5=0 are x=-(-4+sqrt(21))/2 ,x=(4+sqrt(21))/2
Find the zeros of -4x^2+16x+5=0
The zeros of -4x^2+16x+5=0 are x=-(-4+sqrt(21))/2 ,x=(4+sqrt(21))/2