What are the solutions to the equation 0=4x^2-5x-3 ?

The solutions to the equation 0=4x^2-5x-3 are x=(5+sqrt(73))/8 ,x=(5-sqrt(73))/8

Find the zeros of 0=4x^2-5x-3

The zeros of 0=4x^2-5x-3 are x=(5+sqrt(73))/8 ,x=(5-sqrt(73))/8

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0 = 4 x^{2} - 5 x - 3

x = \frac{5 + 73}{8}, x = \frac{5 - 73}{8}

Decimal Notation

x = 1.69300 \dots, x = - 0.44300 \dots

Solution steps

0 = 4 x^{2} - 5 x - 3

Switch sides

4 x^{2} - 5 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

(- 5)^{2} - 4 \cdot 4 (- 3) = 73

x_{1, 2} = \frac{- ( - 5 ) \pm 73}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 73}{2 \cdot 4}, x_{2} = \frac{- ( - 5 ) - 73}{2 \cdot 4}

x = \frac{- ( - 5 ) + 73}{2 \cdot 4} : \frac{5 + 73}{8}

x = \frac{- ( - 5 ) - 73}{2 \cdot 4} : \frac{5 - 73}{8}

The solutions to the quadratic equation are:

x = \frac{5 + 73}{8}, x = \frac{5 - 73}{8}

2 x^{2} + 6 x + 3 = 3

6 x^{2} - 4 x - 4 = 0

7 y + 3 y^{2} = 20

- 29 = 4 z - 17 z^{2} + 13 z^{2}

49 s^{2} + 70 s = - 25

What are the solutions to the equation 0=4x^2-5x-3 ?
The solutions to the equation 0=4x^2-5x-3 are x=(5+sqrt(73))/8 ,x=(5-sqrt(73))/8
Find the zeros of 0=4x^2-5x-3
The zeros of 0=4x^2-5x-3 are x=(5+sqrt(73))/8 ,x=(5-sqrt(73))/8