What are the solutions to the equation 0=2x^2+7x-15 ?

The solutions to the equation 0=2x^2+7x-15 are x= 3/2 ,x=-5

Find the zeros of 0=2x^2+7x-15

The zeros of 0=2x^2+7x-15 are x= 3/2 ,x=-5

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0 = 2 x^{2} + 7 x - 15

x = \frac{3}{2}, x = - 5

Decimal Notation

x = 1.5, x = - 5

Solution steps

0 = 2 x^{2} + 7 x - 15

Switch sides

2 x^{2} + 7 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 ( - 15 )}{2 \cdot 2}

7^{2} - 4 \cdot 2 (- 15) = 13

x_{1, 2} = \frac{- 7 \pm 13}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 13}{2 \cdot 2}, x_{2} = \frac{- 7 - 13}{2 \cdot 2}

x = \frac{- 7 + 13}{2 \cdot 2} : \frac{3}{2}

x = \frac{- 7 - 13}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

x = \frac{3}{2}, x = - 5

- 4.9 x^{2} + 10 x + 2 = 0

5 y^{2} + 1 = 8

3 (3 x - 2) = (x - 4) (x + 4)

4 B = (t + 2)^{2}

6 a^{2} - 2 = 0

What are the solutions to the equation 0=2x^2+7x-15 ?
The solutions to the equation 0=2x^2+7x-15 are x= 3/2 ,x=-5
Find the zeros of 0=2x^2+7x-15
The zeros of 0=2x^2+7x-15 are x= 3/2 ,x=-5